(1)设每辆小客车能坐$x$人,每辆大客车能坐$y$人,
依题意,得:$\left\{\begin{array}{l}2x+y=95\\x+2y=115\end{array}\right.$,
解得:$\left\{\begin{array}{l}x=25\\y=45\end{array}\right.$.
答:每辆小客车能坐$25$人,每辆大客车能坐$45$人.
(2)依题意,得:$25a+45b=500$,
$\therefore a=20-\dfrac{9}{5}b$.
$\because a$,$b$均为非负整数,
$\therefore $当$b=0$时,$a=20$;当$b=5$时,$a=11$;当$b=10$时,$a=2$.
$\therefore $学校共有$3$种租车方案,
方案$1$:租用$20$辆小客车;
方案$2$:租用$11$辆小客车,$5$辆大客车;
方案$3$:租用$2$辆小客车,$10$辆大客车.