Remember that cosecant and secant are cofunctions:
$\csc x= \sec (90-x)$.
Set $ \sec (90-x)$ equal to $\sec 70^{\circ}$ to determine $x$.
$90-x=70$.
$x=20^{ \circ }$.
To check your answer, notice $ \csc 20^{ \circ }= \sec (90-20)^{\circ}$.
If $ \csc x= \sec 70^{ \circ }$, then solve for $x$.
Simone
发布于 2024-11-24 09:19:18
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